1-3-2-6 baccarat strategy
The 1-3-2-6 baccarat strategy is a very simple strategy which may bring you good winnings and if you are unlucky - small losses because the objective of this baccarat strategy is to place small bets with the potential of big return. 1, 3, 2 and 6 are the units that you need to bet in four hands. Let's say that on the first hand you place a bet at the amount of $1. If you come out as a winner, you will have acquired profit of $1. On the second hand you would increase your initial bet by $1 and place a bet of $3. If you win one more time, you will have $6 and on the third hand you need to take away $4, and place a bet of $2 ($6 - $4 = $2). If you win again, you will have $4 on the table and on the next hand you add $2 more for a total bet of $6. If the forth bet wins, you will have $12 on the table, $10 of which are profit. If you lose one of the hands, you need to start all over again from $1.
As you see, with this baccarat strategy the maximum amount that you may lose is $2. If you lose your first bet, you will lose $1. If you have a loss on your second bet, you will lose $2. If you win on the first two hands but lose the third one, you will have a profit of $2. If you lose the forth, you will end up even.
In the long-run, the odds favor the casino and no betting system can change that fact. But that is not to say that this systems can’t work beautifully in the short term.
What makes the 1 – 3 – 2 – 6 system attractive is that you risk only two betting units for a chance to win ten units. You can make a nice profit with a minimal investment.
The first bet is one unit, if you win, add another unit, making the second bet a total of three units. If you win the second bet, there are 6 units on the table. Remove four units, making your third bet two units. If it wins add two more units, making it a total of six units for your fourth bet. If the fourth bet wins you’ll collect a total of 12 units, of which ten units are profit!
If you lose the first bet, the loss is one unit. Assuming you win the first, but lose the second bet, your net loss is two units. If you win the second, but lose the third bet, you have a profit of two units. If you win the first three bets but lose the fourth bet, you'll break even.
If you lose the second bet five out of six times and win four consecutive bets once, you’ll be right back to even. You can also use this system for even-money betting at any other casino game.
As you see, with this baccarat strategy the maximum amount that you may lose is $2. If you lose your first bet, you will lose $1. If you have a loss on your second bet, you will lose $2. If you win on the first two hands but lose the third one, you will have a profit of $2. If you lose the forth, you will end up even.
In the long-run, the odds favor the casino and no betting system can change that fact. But that is not to say that this systems can’t work beautifully in the short term.
What makes the 1 – 3 – 2 – 6 system attractive is that you risk only two betting units for a chance to win ten units. You can make a nice profit with a minimal investment.
The first bet is one unit, if you win, add another unit, making the second bet a total of three units. If you win the second bet, there are 6 units on the table. Remove four units, making your third bet two units. If it wins add two more units, making it a total of six units for your fourth bet. If the fourth bet wins you’ll collect a total of 12 units, of which ten units are profit!
If you lose the first bet, the loss is one unit. Assuming you win the first, but lose the second bet, your net loss is two units. If you win the second, but lose the third bet, you have a profit of two units. If you win the first three bets but lose the fourth bet, you'll break even.
If you lose the second bet five out of six times and win four consecutive bets once, you’ll be right back to even. You can also use this system for even-money betting at any other casino game.